2(x^2-3x+2)-2(x^2+8x+7)=1

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Solution for 2(x^2-3x+2)-2(x^2+8x+7)=1 equation: 


Simplifying
2(x2 + -3x + 2) + -2(x2 + 8x + 7) = 1

Reorder the terms:
2(2 + -3x + x2) + -2(x2 + 8x + 7) = 1
(2 * 2 + -3x * 2 + x2 * 2) + -2(x2 + 8x + 7) = 1
(4 + -6x + 2x2) + -2(x2 + 8x + 7) = 1

Reorder the terms:
4 + -6x + 2x2 + -2(7 + 8x + x2) = 1
4 + -6x + 2x2 + (7 * -2 + 8x * -2 + x2 * -2) = 1
4 + -6x + 2x2 + (-14 + -16x + -2x2) = 1

Reorder the terms:
4 + -14 + -6x + -16x + 2x2 + -2x2 = 1

Combine like terms: 4 + -14 = -10
-10 + -6x + -16x + 2x2 + -2x2 = 1

Combine like terms: -6x + -16x = -22x
-10 + -22x + 2x2 + -2x2 = 1

Combine like terms: 2x2 + -2x2 = 0
-10 + -22x + 0 = 1
-10 + -22x = 1

Solving
-10 + -22x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -22x = 1 + 10

Combine like terms: -10 + 10 = 0
0 + -22x = 1 + 10
-22x = 1 + 10

Combine like terms: 1 + 10 = 11
-22x = 11

Divide each side by '-22'.
x = -0.5

Simplifying
x = -0.5

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